Pankaj Tanwar
Published on

Split a String in Balanced Strings.

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It's day 21 of my coding diary. Yesterday, vercel was having some issues with their build system. Well, it's up and working smooth now. Let's directly move to the problem of the day.

Problem of the day - Split a String in Balanced Strings

Tag - Easy

Balanced strings are those that have an equal quantity of 'L' and 'R' characters.

Given a balanced string s, split it in the maximum amount of balanced strings.

Return the maximum amount of split balanced strings.

Example 1:

Input: s = "RLRRLLRLRL" Output: 4

This is the worst problem statement, I have ever seen. It's really confusing man, all the example test cases are not clear. I spent time unnecessarily, building some dynamic programming logic for this dumb question.

So, the problem says, to find the maximum amount of split balanced strings. It does not clearly talk about the order of L & R.

Mentioning `splitting gives an idea of considering one sub-string having multiple balanced sub-strings as one only. but still, initially, I got confused with logic for considering all corner cases.

It turned out to be the simplest problem with just tracking count of L & R, that's it.

Here is my solution

class Solution {
int balancedStringSplit(string s) {
int res = 0;
int balance = 0;
for(int i=0;i<s.length();i++) {
balance += s[i] == 'L' ? 1 : -1;
if(balance == 0) res++;
return res;

Not to mention, run time 0ms and faster than 100%. Honestly, I am not happy. Such uncleared problems make me less excited about solving more problems.

Well, I will try some good medium problems tomorrow!

Thanks for being part of my daily-code-workout journey. As always, if you have any thoughts about anything shared above, don't hesitate to reach out.

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